Optimal. Leaf size=158 \[ \frac{1}{2} a^2 c x^2+\frac{1}{4} a^2 e x^4+\frac{1}{6} a^2 g x^6+\frac{1}{8} b x^8 (2 a f+b c)+\frac{1}{5} a x^5 (a f+2 b c)+\frac{d \left (a+b x^3\right )^3}{9 b}+\frac{1}{10} b x^{10} (2 a h+b e)+\frac{1}{7} a x^7 (a h+2 b e)+\frac{2}{9} a b g x^9+\frac{1}{11} b^2 f x^{11}+\frac{1}{12} b^2 g x^{12}+\frac{1}{13} b^2 h x^{13} \]
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Rubi [A] time = 0.400245, antiderivative size = 158, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.056 \[ \frac{1}{2} a^2 c x^2+\frac{1}{4} a^2 e x^4+\frac{1}{6} a^2 g x^6+\frac{1}{8} b x^8 (2 a f+b c)+\frac{1}{5} a x^5 (a f+2 b c)+\frac{d \left (a+b x^3\right )^3}{9 b}+\frac{1}{10} b x^{10} (2 a h+b e)+\frac{1}{7} a x^7 (a h+2 b e)+\frac{2}{9} a b g x^9+\frac{1}{11} b^2 f x^{11}+\frac{1}{12} b^2 g x^{12}+\frac{1}{13} b^2 h x^{13} \]
Antiderivative was successfully verified.
[In] Int[x*(a + b*x^3)^2*(c + d*x + e*x^2 + f*x^3 + g*x^4 + h*x^5),x]
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Rubi in Sympy [F] time = 0., size = 0, normalized size = 0. \[ a^{2} c \int x\, dx + \frac{a^{2} e x^{4}}{4} + \frac{a^{2} g x^{6}}{6} + \frac{2 a b g x^{9}}{9} + \frac{a x^{7} \left (a h + 2 b e\right )}{7} + \frac{a x^{5} \left (a f + 2 b c\right )}{5} + \frac{b^{2} f x^{11}}{11} + \frac{b^{2} g x^{12}}{12} + \frac{b^{2} h x^{13}}{13} + \frac{b x^{10} \left (2 a h + b e\right )}{10} + \frac{b x^{8} \left (2 a f + b c\right )}{8} + \frac{d \left (a + b x^{3}\right )^{3}}{9 b} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x*(b*x**3+a)**2*(h*x**5+g*x**4+f*x**3+e*x**2+d*x+c),x)
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Mathematica [A] time = 0.0671372, size = 163, normalized size = 1.03 \[ \frac{1}{2} a^2 c x^2+\frac{1}{3} a^2 d x^3+\frac{1}{4} a^2 e x^4+\frac{1}{8} b x^8 (2 a f+b c)+\frac{1}{5} a x^5 (a f+2 b c)+\frac{1}{9} b x^9 (2 a g+b d)+\frac{1}{6} a x^6 (a g+2 b d)+\frac{1}{10} b x^{10} (2 a h+b e)+\frac{1}{7} a x^7 (a h+2 b e)+\frac{1}{11} b^2 f x^{11}+\frac{1}{12} b^2 g x^{12}+\frac{1}{13} b^2 h x^{13} \]
Antiderivative was successfully verified.
[In] Integrate[x*(a + b*x^3)^2*(c + d*x + e*x^2 + f*x^3 + g*x^4 + h*x^5),x]
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Maple [A] time = 0.001, size = 152, normalized size = 1. \[{\frac{{b}^{2}h{x}^{13}}{13}}+{\frac{{b}^{2}g{x}^{12}}{12}}+{\frac{{b}^{2}f{x}^{11}}{11}}+{\frac{ \left ( 2\,abh+{b}^{2}e \right ){x}^{10}}{10}}+{\frac{ \left ( 2\,abg+{b}^{2}d \right ){x}^{9}}{9}}+{\frac{ \left ( 2\,abf+{b}^{2}c \right ){x}^{8}}{8}}+{\frac{ \left ({a}^{2}h+2\,bea \right ){x}^{7}}{7}}+{\frac{ \left ({a}^{2}g+2\,bda \right ){x}^{6}}{6}}+{\frac{ \left ({a}^{2}f+2\,abc \right ){x}^{5}}{5}}+{\frac{{a}^{2}e{x}^{4}}{4}}+{\frac{{a}^{2}d{x}^{3}}{3}}+{\frac{{a}^{2}c{x}^{2}}{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x*(b*x^3+a)^2*(h*x^5+g*x^4+f*x^3+e*x^2+d*x+c),x)
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Maxima [A] time = 1.41953, size = 204, normalized size = 1.29 \[ \frac{1}{13} \, b^{2} h x^{13} + \frac{1}{12} \, b^{2} g x^{12} + \frac{1}{11} \, b^{2} f x^{11} + \frac{1}{10} \,{\left (b^{2} e + 2 \, a b h\right )} x^{10} + \frac{1}{9} \,{\left (b^{2} d + 2 \, a b g\right )} x^{9} + \frac{1}{8} \,{\left (b^{2} c + 2 \, a b f\right )} x^{8} + \frac{1}{7} \,{\left (2 \, a b e + a^{2} h\right )} x^{7} + \frac{1}{4} \, a^{2} e x^{4} + \frac{1}{6} \,{\left (2 \, a b d + a^{2} g\right )} x^{6} + \frac{1}{3} \, a^{2} d x^{3} + \frac{1}{5} \,{\left (2 \, a b c + a^{2} f\right )} x^{5} + \frac{1}{2} \, a^{2} c x^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((h*x^5 + g*x^4 + f*x^3 + e*x^2 + d*x + c)*(b*x^3 + a)^2*x,x, algorithm="maxima")
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Fricas [A] time = 0.216128, size = 1, normalized size = 0.01 \[ \frac{1}{13} x^{13} h b^{2} + \frac{1}{12} x^{12} g b^{2} + \frac{1}{11} x^{11} f b^{2} + \frac{1}{10} x^{10} e b^{2} + \frac{1}{5} x^{10} h b a + \frac{1}{9} x^{9} d b^{2} + \frac{2}{9} x^{9} g b a + \frac{1}{8} x^{8} c b^{2} + \frac{1}{4} x^{8} f b a + \frac{2}{7} x^{7} e b a + \frac{1}{7} x^{7} h a^{2} + \frac{1}{3} x^{6} d b a + \frac{1}{6} x^{6} g a^{2} + \frac{2}{5} x^{5} c b a + \frac{1}{5} x^{5} f a^{2} + \frac{1}{4} x^{4} e a^{2} + \frac{1}{3} x^{3} d a^{2} + \frac{1}{2} x^{2} c a^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((h*x^5 + g*x^4 + f*x^3 + e*x^2 + d*x + c)*(b*x^3 + a)^2*x,x, algorithm="fricas")
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Sympy [A] time = 0.093544, size = 167, normalized size = 1.06 \[ \frac{a^{2} c x^{2}}{2} + \frac{a^{2} d x^{3}}{3} + \frac{a^{2} e x^{4}}{4} + \frac{b^{2} f x^{11}}{11} + \frac{b^{2} g x^{12}}{12} + \frac{b^{2} h x^{13}}{13} + x^{10} \left (\frac{a b h}{5} + \frac{b^{2} e}{10}\right ) + x^{9} \left (\frac{2 a b g}{9} + \frac{b^{2} d}{9}\right ) + x^{8} \left (\frac{a b f}{4} + \frac{b^{2} c}{8}\right ) + x^{7} \left (\frac{a^{2} h}{7} + \frac{2 a b e}{7}\right ) + x^{6} \left (\frac{a^{2} g}{6} + \frac{a b d}{3}\right ) + x^{5} \left (\frac{a^{2} f}{5} + \frac{2 a b c}{5}\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x*(b*x**3+a)**2*(h*x**5+g*x**4+f*x**3+e*x**2+d*x+c),x)
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GIAC/XCAS [A] time = 0.209178, size = 216, normalized size = 1.37 \[ \frac{1}{13} \, b^{2} h x^{13} + \frac{1}{12} \, b^{2} g x^{12} + \frac{1}{11} \, b^{2} f x^{11} + \frac{1}{5} \, a b h x^{10} + \frac{1}{10} \, b^{2} x^{10} e + \frac{1}{9} \, b^{2} d x^{9} + \frac{2}{9} \, a b g x^{9} + \frac{1}{8} \, b^{2} c x^{8} + \frac{1}{4} \, a b f x^{8} + \frac{1}{7} \, a^{2} h x^{7} + \frac{2}{7} \, a b x^{7} e + \frac{1}{3} \, a b d x^{6} + \frac{1}{6} \, a^{2} g x^{6} + \frac{2}{5} \, a b c x^{5} + \frac{1}{5} \, a^{2} f x^{5} + \frac{1}{4} \, a^{2} x^{4} e + \frac{1}{3} \, a^{2} d x^{3} + \frac{1}{2} \, a^{2} c x^{2} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((h*x^5 + g*x^4 + f*x^3 + e*x^2 + d*x + c)*(b*x^3 + a)^2*x,x, algorithm="giac")
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